Question

Hii guys.....


A mixture of milk and water contains 30% milk. What percent of mixture should be replaced with milk such that the resultant mixture contains milk and water in the ratio
11 : 14....??​

Answer 1

Answer:

the percentage of mixture to be replaced with milk is 22%

Answer 2

20% of the mixture should be replaced.

Step-by-step explanation:

Let, total mixture = 100 units

Then according to the question,

• milk = 30 units
• water = (100 - 30) units = 70 units

Let, x units of mixture should be replaced with milk.

Then mixture left = (100 - x) units

In (100 - x) units of mixture,

• water = (100 - x) × $\dfrac{70}{100}$ units
• milk = (100 - x) × $\dfrac{30}{100}$ units

When x units of milk is added, amount of milk

= (100 - x) × $\dfrac{30}{100}$ + x units

By the given condition,

(100 - x) × $\dfrac{30}{100}$ + x : (100 - x) × $\dfrac{70}{100}$ = 11 : 14

⇒ (100 - x) × $\dfrac{3}{10}$ + x : (100 - x) × $\dfrac{7}{10}$ = 11 : 14

⇒ $\dfrac{300 - 3x + 10x}{10}$ : $\dfrac{700 - 7x}{10}$ = 11 : 14

⇒ $\dfrac{300+7x}{10}$ : $\dfrac{700-7x}{10}$ = 11 : 14

⇒ (300 + 7x) : (700 - 7x) = 11 : 14

⇒ $\dfrac{300+7x}{700-7x}=\dfrac{11}{14}$

⇒ 4200 + 98x = 7700 - 77x

⇒ 175x = 3500

⇒ x = 20

So, 20% of the mixture should be replaced.

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