Question

Hii Guys....
.
.
A particle moves 20 m in 3rd second and 30 m in 5th second of its journey. what will be the distance covered by the body in 4s after 6th second.
.
.
please answer fast... I will mark the correct one as Brainlist answer..! ​

Answer 1

Answer:

Hello

Step-by-step explanation:

Given that the motion is in 1 Dimension and the body doesn't change it's direction (i.e. velocity is in the direction of acceleration), we have:

s=u+a(2t−1)/2

12 = u + a(2*2 - 1)/2

=> 12 = u + 3a/2

=> 2u + 3a = 24

and

20 = u + a(2*4 - 1)/2

20 = u + 7a/2

=> 2u + 7a = 40

From 1 and 2:

a = 4

u = 6

Now, distance covered in 4s after 5th second = Distance covered in 9 seconds - distance covered in 5 seconds

= 6*9 + 1/2 * 4 * 9 * 9 - (6 * 5 + 1/2 * 4 * 5 * 5)

= 54 + 162 - (30 + 50)

= 136 m

Answer 2

Answer:

The problem in Patalpuram was that there was a lack of clean drinking water and proper sanitation. In addition, people were dying of water-borne diseases and there was a shortage of proper medical facilities