Question

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Answer 1

Explanation:

let the distance between them be s ..

then,

by Newton's second law.

s = ut + 1/2 at^2

for train A,

now, u = 72 km/h = 20 m/s

t = 50 sec

a = 0 ( since it is moving with an uniform velocity )

s = 20 × 50 + 0 = 1000m

For train B,

u = 20 m/s

a = 1 m/s^2

t = 50 sec.

S2 = 20 ×50 + 1/2 × 50 × 50 = 2250m

Length of both trains = 2 × 400 = 800 m

Hence, the original distance between train A and B is 2250 - 1000 - 800 =450 m

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Answer 2

Answer:

Relative velocity VAB = VA - VB

But velocities are the same,

So 20m/s - 20m/s = 0 m/s

Let's assume A is stationary, so distance travelled by B

S = VABt + 1/2 × a × t^2

S = 0 + 1/2 × 1 × 50 × 50

S = 1250m

Now, we should subtract the lengths of the trains

1250 - (400+ 400)

450m