Math, asked by yuuu6, 8 months ago

Hii guys goodnight help me to do it
The denominator of a fraction is greater than the numerator by 8 and if the numerator is increased by 17 and the denominator decreased by 1 then the fraction becomes 3/2 find the fraction.
Proper explanation is required

Answers

Answered by Anonymous

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Answer:

The fraction is $1\frac{8}{39}$

Step-by-step explanation:

Let, the numerator of the fraction be, 'x'

The denominator is greater than the numerator by 8

So, the is denominator is = (x+8)

When the numerator gets increased by 17 then, the numerator becomes

= (x+17)

When the denominator gets decreased by 1 then the denominator becomes

= (x+8)-1

=(x+8-1)

= (x+7)

So, the new fraction obtained is = (x+17)/(x+7)

According to the problem,

(x+17)/(x+7) = 2/3

⇒ 3 × (x+17) = 2×(x+7)

[∵ When change the sides of the integers then the respective sign of the integers too gets changed such as, (+) to (-), (×) to (÷) and vice versa.]

⇒ 3x +51 = 2x +14

⇒ 3x-2x = 14-51

⇒ x = -47

So, the numerator is -47

∴ The denominator is $= (-47+8)\\ = -39$

So, the fraction is $= -47/-39\\ = 47/39$

= $1\frac{8}{39}$

[∵ (+)× (+) = (+)

(-)×(-) = (+)

(+)×(-) =(-)

(-)×(+) = (-)]

Follow: https://brainly.in/question/13385331 for the similar content

Answered by realakv

Answer:

13/21...

Step-by-step explanation:

Let fraction be x/(x+8)

Then firstly (x+17)/(x+7)=3/2

2x+34=3x+21

x=13 and x+8=13+8=21

Hence the fraction be 13/21...

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