Hii guys goodnight help me to do it
The denominator of a fraction is greater than the numerator by 8 and if the numerator is increased by 17 and the denominator decreased by 1 then the fraction becomes 3/2 find the fraction.
Proper explanation is required
Answers
Answer:
The fraction is
Step-by-step explanation:
Let, the numerator of the fraction be, 'x'
The denominator is greater than the numerator by 8
So, the is denominator is = (x+8)
When the numerator gets increased by 17 then, the numerator becomes
= (x+17)
When the denominator gets decreased by 1 then the denominator becomes
= (x+8)-1
=(x+8-1)
= (x+7)
So, the new fraction obtained is = (x+17)/(x+7)
According to the problem,
(x+17)/(x+7) = 2/3
⇒ 3 × (x+17) = 2×(x+7)
[∵ When change the sides of the integers then the respective sign of the integers too gets changed such as, (+) to (-), (×) to (÷) and vice versa.]
⇒ 3x +51 = 2x +14
⇒ 3x-2x = 14-51
⇒ x = -47
So, the numerator is -47
∴ The denominator is
So, the fraction is
=
[∵ (+)× (+) = (+)
(-)×(-) = (+)
(+)×(-) =(-)
(-)×(+) = (-)]
Follow: https://brainly.in/question/13385331 for the similar content
Answer:
13/21...
Step-by-step explanation:
Let fraction be x/(x+8)
Then firstly (x+17)/(x+7)=3/2
2x+34=3x+21
x=13 and x+8=13+8=21
Hence the fraction be 13/21...