Question

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Please answer this question❤❤❤❤
Distinguish between estrification and saponication reactions with the help of chemical equations for each❤❤❤❤❤​

Answer 1

Explanation:

Esterfication reaction: when an organic acid reacts with an alcohol in the presence of acid catalyst, it produces a sweet smelling substance called ester. this reaction is called esterfication reaction, e.g.,

CH3COOH + C2H50H ---------> CH3COOC2H5 +H2O

 

Saponification: ester reacts in the presence of an acid or a base to give back the alcohol and the carboxylic acid. this reaction is known as saponification because it is used in the preparation of soap.

Answer 2

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Esterification is the process by which esters are formed when an alcohol reacts with an acid in presence of conc. Sulphuric acid. R'OH + RCOOH +RCOOR' + H2O CH3CH2OH + CH3COOH + CH3COOC2H5 + H20 Saponification reaction is when ester reacts with NaOH, to form sodium salt of acid and alcohol. RCOOR' + NaOH +RCOONa+R'OH CH3COOC2H5 + NaOH + CH3COONa+ C2H5OH Esters are used in making perfumes, artificial flavouring agents, ice-creams, cold drinks. Saponification process is used in making soaps.