Question

hii guys... plzzz answer this question

Answer 1

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Answer 2

$\boxed{ANSWER...}$

Given ,

BA perpendicular on AC.
DE perpendicular on DF.

Therefore ,

Angle A = 90°
Angle D = 90°

AB = DE
BF = EC

In ∆ABC and ∆DEF ,

AB = DE (given)

AngleA = AngleD (given)

BF = EC (given)

Therefore , by SAS criteria ,

∆ABC ~= ∆DEF..