Question

Hii Guys....

Solve it...By RegulA Falsi Method....✌☺​

Answer 1

Answer:

hey.. ❤

➡ f(x)=x3−x−1=0 has only one real root, which is on the intervall [1,2].

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➡f(1)=−1<0 and f(2)=5>0 so f(1)⋅f(2)<0

➡We suppose that there are two roots, a and b. Then we have that f(a)=f(b)=0.

The function f is continuous on [a,b] and differentiable on (a,b).

➡So, from Rolle's Theorem there is a c∈(a,b) such that f′(c)=0⇒3c2−1=0.

Answer 2

hope it's help you... bhai.. ✌