Question

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Answer 1

Answer:

${x}^{3} + {3x}^{2} + 3x + 1 \\ x + 1 = 0 \\ x = - 1 \\ ({ - 1})^{3} + {3} ( { - 1})^{2} + 3 ( - 1)+ 1 \\ - 1 + 3 - 3 + 1 \\ 0$

Answer 2

Answer:

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 ⟹x³+3x²+3x+1

 ⟹x+1=0

 ⟹x=−1

 ⟹(−1)³+3(−1)²+3(−1)+1

 ⟹−1+3−3+1

 ⟹0