Math, asked by Anonymous, 8 months ago

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Answered by jnbaledr
2

Answer:

Area of triangle = 1/2 *b*h

ABC and BCD are triangles lying between same parallels and having same base BC.

Area of triangle ABC = 1/2 *BC*AP. (A1)

Area of triangle BCD = 1/2 *BC*AP. (A2)

A1:A2 = 1:1

Answered by dp14380dinesh
2

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Area of triangle = 1/2 *b*h

ABC and BCD are triangles lying between same parallels and having same base BC.

Area of triangle ABC = 1/2 *BC*AP. (A1)

Area of triangle BCD = 1/2 *BC*AP. (A2)

A1:A2 = 1:1

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