Physics, asked by Anonymous, 1 year ago

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Here is my question ⤵️⤵️
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A copper plate has an area of 250cm^2 at 0°C. Calculate the area of this plate at 60°C. Given [coefficient of linear expansion of copper is alpha l=1.7×10^-5°C^-1
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ItzPrincessNk: Why?
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Answers

Answered by ItzPrincessNk
8

Hii Dear Sis!❤️

Your Answer:

250.471cm²

Explanation:

Problem Given:

A copper plate has an area of 250cm^2 at 0°C. Calculate the area of this plate at 60°C. Given [coefficient of linear expansion of copper is alpha l=1.7×10^-5°C^-1.

Solution:

Given :

=>Copper plate area=A₀=250cm²

[I am assuming linear expansion of copper as :1.7x 10⁻⁵ C⁻¹  ]

=>Here, is the method :β=2α=2x1.7x 10⁻⁵ C⁻¹

=>3.4x10⁻⁵ C⁻¹

ΔT=>(60-0)=60°

Aθ=>A₀(1+βΔT)

A₆₀=>50(1+3.14x10⁻⁵ x60)=250(1+0.001884)=250.471cm²

Area of copper plate at 60 degree=250.471cm²

Hence,Its Done and proved!

^_^

Hope My Answer Helps You!

Keep SmilinG!


Anonymous: tysm sis....
Anonymous: ur answer really helped me...
ItzPrincessNk: Thanks for Brainliest! ^^"
Anonymous: wello sis ^_^
Answered by Blaezii
6

Hi Dear sisu!❤️❤️

Your Answer:

Area of copper plate at 60 degree=250.471cm²

Explanation:

=>The actual value of cofficient of linear expanison of copper is 1.7×10^(-5)°C^(-1 )              

=>So, the cofficient of areal expanison = 3.4×10^( -5 )

=>Formula of Intial area×(1+(Expanison Coffiecient×Temperature Increase))"

=>In this case after applying formula it will be:

=> New,Area 250×[ 1+ 3.4 × 10 ^(-5)×(60 - 0)]

But this is very small differnce as compared to original size.

So,This final area will be:

=> New,area 50(1+3.14x10⁻⁵ x60)=250(1+0.001884)=250.471cm²

Area of copper plate at 60 degree=250.471cm²

Hope It Helps You!❤️❤️


Anonymous: tysm bro....
Anonymous: ur answer really helped me a lot...
Blaezii: Wello ^^"
Anonymous: ^_^
Anonymous: y bro ?
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