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A copper plate has an area of 250cm^2 at 0°C. Calculate the area of this plate at 60°C. Given [coefficient of linear expansion of copper is alpha l=1.7×10^-5°C^-1
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Answers
Hii Dear Sis!❤️
Your Answer:
250.471cm²
Explanation:
Problem Given:
A copper plate has an area of 250cm^2 at 0°C. Calculate the area of this plate at 60°C. Given [coefficient of linear expansion of copper is alpha l=1.7×10^-5°C^-1.
Solution:
Given :
=>Copper plate area=A₀=250cm²
[I am assuming linear expansion of copper as :1.7x 10⁻⁵ C⁻¹ ]
=>Here, is the method :β=2α=2x1.7x 10⁻⁵ C⁻¹
=>3.4x10⁻⁵ C⁻¹
ΔT=>(60-0)=60°
Aθ=>A₀(1+βΔT)
A₆₀=>50(1+3.14x10⁻⁵ x60)=250(1+0.001884)=250.471cm²
Area of copper plate at 60 degree=250.471cm²
Hence,Its Done and proved!
^_^
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Hi Dear sisu!❤️❤️
Your Answer:
Area of copper plate at 60 degree=250.471cm²
Explanation:
=>The actual value of cofficient of linear expanison of copper is 1.7×10^(-5)°C^(-1 )
=>So, the cofficient of areal expanison = 3.4×10^( -5 )
=>Formula of Intial area×(1+(Expanison Coffiecient×Temperature Increase))"
=>In this case after applying formula it will be:
=> New,Area 250×[ 1+ 3.4 × 10 ^(-5)×(60 - 0)]
But this is very small differnce as compared to original size.
So,This final area will be:
=> New,area 50(1+3.14x10⁻⁵ x60)=250(1+0.001884)=250.471cm²
Area of copper plate at 60 degree=250.471cm²
Hope It Helps You!❤️❤️