hii!!
how to find n=81
because counting in hand is a difficult task
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The first natural number which is a multiple of 11 and has 3 digits is 110.
The last natural number which is multiple of 11 and has 3 digits is 990.
we can write 110=11x10
and 990=11x90.
It means there are 90-10 natural numbers and 1 natural number that is 110
so total =80+1=81
because 990=110 + (n-1)d.
990=110 + (n-1)x11
990-110=11n-11
880+11=11n
891=11n
n=891/11=81
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hope this helps you ....
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