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CLASS 11
according to rotational motion
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Anonymous:
T R = I ALPHA
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Hola User________________
Here is Your Answer...!!!
__________________________
⭐Actually welcome to the concept of the Rotational Dynamics...
⭐Basically we know that ,
⭐Torque on a body is given as .
⭐Tau = I alpha
⭐where I is the moment of inertia and Alpha is the angular acceleration
⭐Now if we see here in the case of the Pulley
⭐Tension is acting as the Force applied here with perpendicular distance of Radius R
⭐so we can write
⭐Torque = F x R
⭐thus tau = T × R ... ( in this case T = F )
⭐thus equating both the equations we get the relation as
⭐T . R = I . alpha
⭐so here the angular acceleration will be given as .
⭐APLHA ( @) = T.R / I
_________________________
Hope it helps u....☺
Here is Your Answer...!!!
__________________________
⭐Actually welcome to the concept of the Rotational Dynamics...
⭐Basically we know that ,
⭐Torque on a body is given as .
⭐Tau = I alpha
⭐where I is the moment of inertia and Alpha is the angular acceleration
⭐Now if we see here in the case of the Pulley
⭐Tension is acting as the Force applied here with perpendicular distance of Radius R
⭐so we can write
⭐Torque = F x R
⭐thus tau = T × R ... ( in this case T = F )
⭐thus equating both the equations we get the relation as
⭐T . R = I . alpha
⭐so here the angular acceleration will be given as .
⭐APLHA ( @) = T.R / I
_________________________
Hope it helps u....☺
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