Math, asked by riya2237, 1 year ago

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The number of integers greater than 6000 that can be formed using the digits 3, 5, 6, 7 and 8 without repetition is ?

by permutations and combination

Answers

Answered by nhkmk786
5
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4 digit no. starting from 6 r 4.3.2=24

4 digit no. starting from 7 r 4.3.2=24

4 digit no. starting from 8 r 4.3.2=24

5 digit no. starting from3 r 4.3.2.1=24

5digit no. starting from 5 r 4.3.2.1=24

5 digit no. starting from 6 r 4.3.2.1=24

5 digit no. starting from 7 r 4.3.2.1=24

5 digit no. starting from 8 r 4.3.2.1=24

total intigers greater then 6000=24+24+24+24+24+24+24+24=192

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Answered by inficom836
1

(i)87653

(ii)86753

(iii)85763

(iv)85673

(v)83765

(vi)83675

(vii)83567

(viii)83576

∴ The number is (8*5)= 40

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