hii mates
solve by split method
→ x²+6x+5
Anonymous:
Is the given Eqn =0 ,?
Answers
Answered by
7
hii mate✌✌
_________
here is ur answer ^↓^
________________
✒✒By split method
⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵
→ x²+6x+5
→ x²+5x+1x+5
→ x (x+5)+1 (x+5)
→ (x+1)(x+5)
values are ↓↓
→ x = (-1)✔
&&&&&&&
→ x = (-5)✔✔
_____________
⭐⭐hope it helps uh⭐⭐
_________
here is ur answer ^↓^
________________
✒✒By split method
⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵
→ x²+6x+5
→ x²+5x+1x+5
→ x (x+5)+1 (x+5)
→ (x+1)(x+5)
values are ↓↓
→ x = (-1)✔
&&&&&&&
→ x = (-5)✔✔
_____________
⭐⭐hope it helps uh⭐⭐
Answered by
4
hloo frnd and your answer is as follows....
----> x2 + 6x + 5
----> x2 + (5+1)x + 5
----> x2 + 5x + x + 5
----> x ( x + 5 ) + 1 ( x + 5 )
----> ( x + 5 ) ( x + 1 )
----- x = -5 , -1
hope it helps u.....☺☺
----> x2 + 6x + 5
----> x2 + (5+1)x + 5
----> x2 + 5x + x + 5
----> x ( x + 5 ) + 1 ( x + 5 )
----> ( x + 5 ) ( x + 1 )
----- x = -5 , -1
hope it helps u.....☺☺
hmm
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