hii ...
please solve these qstns.. please, please,, anyone ..
in 21, i have taken the nos. as a, a+n, a-n..
and their sum as =-3 ... please slov e the further qstn..
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Let the numbers be ( a - d ) , a , ( a + d ).
Given,
⇒Sum of the terms = -3
⇒( a - d ) + a + ( a + d ) = -3
⇒a - d + a + a + d = -3
⇒3a = -3
⇒ a = ( -3 ) ÷3
•°• a = -1
Now,
⇒Product of numbers = 8
⇒ ( a - d ) ( a + d ) a = 8
Using identity,
⇒ ( x + y ) ( x - y ) = x² - y²
⇒ ( a² - d² ) a = 8
Substituting the value of ( a = -1 ),
⇒ [ ( -1 )² - d² ] ( -1 ) = 8
⇒ [ 1 - d² ] ( -1 ) = 8
⇒ -1 + d² = 8
⇒ d² = 8 + 1
⇒ d² = 9
⇒ d = √9
•°• d = 3
Now,
Numbers = ( a - d ) , ( a ) , ( a + d )
= [ ( -1 ) - 3 ] , ( -1 ) , [ ( -1 ) + 3 ]
= ( -1 - 3 ) , ( -1 ) , ( -1 + 3 )
= ( -4 ) , ( -1 ) , ( 2 )
Hence, the numbers are -4 , -1 and 2.
Given,
⇒Sum of the terms = -3
⇒( a - d ) + a + ( a + d ) = -3
⇒a - d + a + a + d = -3
⇒3a = -3
⇒ a = ( -3 ) ÷3
•°• a = -1
Now,
⇒Product of numbers = 8
⇒ ( a - d ) ( a + d ) a = 8
Using identity,
⇒ ( x + y ) ( x - y ) = x² - y²
⇒ ( a² - d² ) a = 8
Substituting the value of ( a = -1 ),
⇒ [ ( -1 )² - d² ] ( -1 ) = 8
⇒ [ 1 - d² ] ( -1 ) = 8
⇒ -1 + d² = 8
⇒ d² = 8 + 1
⇒ d² = 9
⇒ d = √9
•°• d = 3
Now,
Numbers = ( a - d ) , ( a ) , ( a + d )
= [ ( -1 ) - 3 ] , ( -1 ) , [ ( -1 ) + 3 ]
= ( -1 - 3 ) , ( -1 ) , ( -1 + 3 )
= ( -4 ) , ( -1 ) , ( 2 )
Hence, the numbers are -4 , -1 and 2.
Niksnikita:
thnqq so much..
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