Question

hii....pls..explain also...

Answer 1

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Your answer is Option. (C)

$\bold{explanation}$

$= > {10}^{ \frac{x}{2} + 1 } \\ \\ = > {10}^{ \frac{x}{2} } × 10 - - - - (1.) \\ \\ we \: know \: that \\ \\ {10}^{x} = 64 \\ \\ mutiply \: both \: sides \: by \: root \\ \\ {10}^{ \frac{x}{2} } = {64}^{ \frac{1}{2} } \\ \\ {10}^{ \frac{x}{2} } = 8 \\ \\ put \: the \: value \: of \: {10}^{ \frac{x}{2} } in \: eq(1) \\ \\ = > 8 \times 10 \\ \\ = > 80$

Answer 2

We know that :

$\clubsuit$  $a^m \times a^n = a^(^m^+^n^)$

Given : $10^x = 64$

Multiplying Both sides with 10², We get :

⇒ $10^x \times 10^2 = 64 \times 100$

⇒ $10^(^x^+^2^) = 6400$

Applying Square root on Both Sides, We get :

⇒ $\sqrt{10^(^x^+^2^)} = \sqrt{6400}$

⇒ $10^\frac{x + 2}{2} = 80$

⇒ $10^\frac{x}{2}^+^1 = 80$

Option C is the Answer