hii..pls solve que 7
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HEY Buddy.....!! here is ur answer
Given that x³+1/x³ = 110
As we know that... a³+b³ = (a+b)³–3ab(a+b)
Here, a = x and b = 1/x
x³+1/x³ = (x+1/x)³–3x.1/x(x+1/x)
=> x³+1/x³ = (x+1/x)³–3(x+1/x)
=> 110 = (x+1/x)³–3(x+1/x)
Here we have to apply the option.....
On taking 5 as first Option....
On taking (x+1/x) = 5
=> 110 = (5)³–3×5
=>110 = 125–15
=> 110 = 110
L.H.S. = R.H.S.
Therefore the value of (x+1/x) = 5 <<< Ans.
I hope it will be helpful for you.....!!
THANK YOU ✌️✌️
MARK IT AS BRAINLIEST
Given that x³+1/x³ = 110
As we know that... a³+b³ = (a+b)³–3ab(a+b)
Here, a = x and b = 1/x
x³+1/x³ = (x+1/x)³–3x.1/x(x+1/x)
=> x³+1/x³ = (x+1/x)³–3(x+1/x)
=> 110 = (x+1/x)³–3(x+1/x)
Here we have to apply the option.....
On taking 5 as first Option....
On taking (x+1/x) = 5
=> 110 = (5)³–3×5
=>110 = 125–15
=> 110 = 110
L.H.S. = R.H.S.
Therefore the value of (x+1/x) = 5 <<< Ans.
I hope it will be helpful for you.....!!
THANK YOU ✌️✌️
MARK IT AS BRAINLIEST
pathak13:
tnx
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