Question

Hii plz solve the 1.32 part 1 and 2

Answer 1

(i) As per first process

Ag = 0.5 g

AgCl= 0.66 g

Therefore Cl = 0.66 - 0.5 = 0.16 g

Ag : Cl = 0.5/0.16 = 25/8

Ag : Cl = 25 : 8

( ii) As per second process

Ag = 1 g

AgCl= 1.32 g

Therefore Cl = 1.32 - 1 = 0.32 g

Ag : Cl = 1/0.32 = 25/8

Ag : Cl = 25 : 8

Hence the data is according to the law of constant proportion