Question

Hii !!

Solve some simple question .

NDA :-2020 ​

Answer 1

Answer:

√2 + 1

Step-by-step explanation:

let the whole thing be x

Then x = 2 + 1/x as it is the same pattern that goes to infinity

x^2- 2x -1 =0

x = (2 + √8)/2

x = √2 + 1

Answer 2

Step-by-step explanation:

$\bold {Given} \ x = \frac{1}{2 + \frac{1}{{2 + \frac{1}{2 + \infty}}}}$

Let,

$\Rightarrow x = \frac{1}{2 + \frac{1}{2 + \frac{1}{2 + \infty} } }$

It can be written as,

$\Rightarrow x = 2 + \frac{1}{x}$

⇒ x² = 2x + 1

⇒ x² - 2x - 1 = 0

⇒ x = 1 ± √2

Hope it helps!