Question

Hii !

Solve this simple question!​

Answer 1

Answer:

Option : D is correct

$\alpha \: and \: \beta \: are \: the \: roots \: of \: \\ \\ {x}^{2} + x + 1 = 0$

here a=1 , b=1 and c=1

$\alpha + \beta = \frac{ - b}{a} = - 1$

and

$\alpha \beta = \frac{c}{a } = 1$

Now soln refers to the attachment

Formula used :

$\boxed{ \rightarrow \: \bold{ {x}^{2} + {y}^{2} = {(x + y)}^{2} - 4xy}} \\ \\ \boxed{\rightarrow \: \bold {{x}^{3} + {y}^{3 } = (x + y)( {x}^{2} + {y}^{2} - xy)}}$

Answer 2

option D...

2 is answer