Question

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Chemistry question is here--

Calculate the number of aluminium ions in 0.051 gram of aluminium oxide(Al2O3).

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Answer 1

ANSWER....

Calculation of number of moles in 0.051 gram of Al2O3.

Molecular mass of Al2O3 =

2 × Atomic mass of Al+3*Atomic mass of O

= (2 × 27g) + (3 × 16g)

= 102 gram

Now,

102 g of Al2O3 = 1 mol

∴0.051 g of Al2O3 = (0.051g/102g) × (1 mol)

= 0.0005 mol.

Now, calculation of no. of Aluminium ions in 0.001 mole of Al2O3.

1 mole of Al2O3 contain Al atoms =

2 × Avogadro number

0.0005 mole of Al2O3 contain Al atoms =

2 × 0.0005 × Avogadro number

= 2 × 0.0005 × 6.022 × 10²³

= 6.022 × $10^{20}$ atoms

In AL2O3 , valency of Al = 3+

Therefore, number of aluminium ions = 6.022 × 10^20 ions..

Answer 2

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