hiii....alll ☺️
plzzz .....give me the answer of question number 16.
of chapter:-ARITHMETIC PROGRESSION.
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17th term differs by 20 from 13th term let's take first term of a A.P. be a and common difference of A.P.be d. Then 10th term of the A.P. be a+9d=52..(1)
17th term is a+16d and 13th term is a+12d. difference =a+16d-a-12d=4d which is given as 20. So d=5. Substitute d=5 in (1), a+9d=52=>a+9(5)=52=>a=52-45=>a=7.
So A.P. follows 7,12,17,22,27,32,37,42,47,52,57,62,67,72,77,82,87,92,97,102,.. so on.
17th term is a+16d and 13th term is a+12d. difference =a+16d-a-12d=4d which is given as 20. So d=5. Substitute d=5 in (1), a+9d=52=>a+9(5)=52=>a=52-45=>a=7.
So A.P. follows 7,12,17,22,27,32,37,42,47,52,57,62,67,72,77,82,87,92,97,102,.. so on.
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