Math, asked by sowmiya35, 1 year ago

hiii dear can u solve

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Answers

Answered by SahilChandravanshi
3
hope this will help you... :-)
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sowmiya35: i have a doubt
sowmiya35: y u did h/h/2
sowmiya35: in your dp it is said that you have logged out?
Answered by Anonymous
2

Answer:

1:7

Step-by-step explanation:

If the cone is divided in two Equal parts from height ,

The Triangle AMD and ANC are similar ( by AAA similarity)

So AM/AN = MD/NC

Or 5/10 = r/R

or R =2r

The Volume of the upper small cone of height 5cm

=1/3(πr²h)

=πr²5/3


And Volume of the frustum BCDE

=Volume of whole cone of height 10 cm - volume of small cone height 5cm

=1/3[πR²10 -πr²5]

=1/3[5π(2R² -r²)]

=5π[2(2r)² -r²]/3

=5π[8r²-r²]/3

=5π(7r²)/3

=35πr²/3

So the ratio of Volumes

=(5πr²/3)/(35πr²/3)

=5/35

=1/7

=1:7

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Anonymous: wait I forgot to add diagram
sowmiya35: thank you broly
Anonymous: Your welcome
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