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▶️define internal resistance of a cell using potentiometer determine the internal resistance of cell?
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Secondary SchoolPhysics 13 points
To find the internal resistance of a cell using potentiometer readings
Ask for details Follow Report by SharveshV6831 20.01.2019
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gadakhsanket
gadakhsanket Ace
Hey dear,
It's a big experiment. I'll only explain the calculation part.
◆ Potentiometer -
A potentiometer is a three-terminal resistor with a sliding or rotating contact that forms an adjustable voltage divider.
◆ Experiment -
[Refer to the diagram for arrangements]
Let l1 be null point obtained when key K1 is closed,
E = Kl1 = (S+r)I ...(1)
V = Kl2 = SI ...(2)
Dividing (1) by (2),
(S+r)/S = l1/l2
r = S(l1-l2)/l2
Therefore, internal resistance of the potentiometer is S(l1-l2)/l2 .
Answer:
Potentiometer. Potentiometer is a device used to measure the internal resistance of a cell, to compare the e.m.f. of two cells and potential difference across a resistor.
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