Question

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▶️define internal resistance of a cell using potentiometer determine the internal resistance of cell?​

Answer 1

Secondary SchoolPhysics 13 points

To find the internal resistance of a cell using potentiometer readings

Ask for details Follow Report by SharveshV6831 20.01.2019

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gadakhsanket

gadakhsanket Ace

Hey dear,

It's a big experiment. I'll only explain the calculation part.

◆ Potentiometer -

A potentiometer is a three-terminal resistor with a sliding or rotating contact that forms an adjustable voltage divider.

◆ Experiment -

[Refer to the diagram for arrangements]

Let l1 be null point obtained when key K1 is closed,

E = Kl1 = (S+r)I ...(1)

V = Kl2 = SI ...(2)

Dividing (1) by (2),

(S+r)/S = l1/l2

r = S(l1-l2)/l2

Therefore, internal resistance of the potentiometer is S(l1-l2)/l2 .

Answer 2

Answer:

Potentiometer. Potentiometer is a device used to measure the internal resistance of a cell, to compare the e.m.f. of two cells and potential difference across a resistor.

hope it will help you ❤️❤️

From shivi........⏭️⏭️