Question

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●【Question from class 11 standard•】
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Q-Calculate the temperature at which the root mean square velocity of SO gas molecule is same as that of O2 molecules at 127℃. Molecular weights of O2 and SO2 are 32 and 64 respectively.

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Answer 1

As we know root mean square velocity =√3RT/M

As velocity is directly proportional to√T/M

As VSO2 =VO2

So √T/64 = √400/32

T/64 = 400/32

T= 400× 64/32 = 800K

So temperature at which velocity of So2 molecule is same is 800 k or 800 -273 = 527 C

Answer 2

Root mean square velocity = √3RT/M or √3PV/M

For O2 molecules,

= √3 × R × 400K / 32

= √3 RT / 32

For SO2 molecules,

= √3 × R × T / 64

= √3 RT / 64

Now,

√3× R × 400 / 32 = √3 × R T / 64

400 / 32 = T / 64

T = 400 × 64 / 32

T = 400 × 2 = 800K

Temperature, T = 800k or 800 - 273 = 527 °C