Question

Hiii guys....!!!!!!❤❤
Here is ur question......!!!!

√3x^2 - 2x - 8√3 = 0
solve by factorisation method..........

Answer 1

$\sqrt{3}x^2-2x-8\sqrt3$

First multiply coefficient of x² with constant term

√3 × 8√3 = 24

Now we need to find factors of 24 which when added or subtracted give us -2

$\sqrt3 x^2 -6x + 4x - 8\sqrt3$

6 can be written as √3 × √3 × 2

∴ $\sqrt3 x^2 -\sqrt 3 \times \sqrt 3 \times 2x + 4x -8\sqrt3$

$\sqrt3 x(x-2\sqrt 3)+4(x-2\sqrt 3)$

$(x-2\sqrt 3)(\sqrt 3x+4)$