Question

hiii .....
help me to solve this question...

Answer 1

I hope It helped you ...

Answer 2

Hi friend,

Here is your answer,
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sec(90°- Ф)cosecФ - tan(90°- Ф)cotФ + cos²25° + cos²65°
                             3tan27°tan63°

=> cosecФ.cosecФ - cotФ.cotФ + cos²25° + sin (90°-65°)
                              3tan27°cot(90°-63°)

=> cosec²Ф - cot²Ф + cos²25° + sin²25Ф 
                     3tan27°cot27°
=>     1  +  1   
           3 * 1

=>  2 
      3
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