Question

hiii mates ..... Please find PR



jaldiiii please​

Answer 1

Step-by-step explanation:

In Triangle PQR

angle Q = 90°

therefore by using Pythagoras thm

we get,

PQ^2+QR^2=PR^2

25+(25-x)2= x^2

625+25+x^2-50x=x^2

650=50x

x= 13

therefore PR= 13 and QR=(25-13)=12