Question

Hiii two balls of different masses are thrown vertically upward with same initial speed which one will rise to the greater height?

Answer 1

Hey mate here is your answer :

v^2 = u^2 + 2*a*s ….here v is the final velocity, u is the initial velocity, a is the acceleration and s is the distance covered.

It is clear from the above, that the distance moved by a body while accelerating/decelerating from an initial velocity u to a final velocity v is NOT dependent on its mass.

In case of vertical projection as the one mentioned in the question, the acceleration due to gravity is the cause of deceleration/retardation of the balls shot upwards with some velocity. As a result, the balls slow down and their velocity becomes zero at the maximum height. So the equation becomes-

(0)^2 = u^2 - 2*g*s [as final velocity is 0 & acceleration is -g]

=> s = (u^2)/2g

As values of u and g will be same for both the balls, so they will share the same value of s too and hence, they will rise to the same height.


I hope this will help you .