Question

Hiiiii!!! Can someone pls help me with this question below

Identify the type of motion of an object in the

following cases:



(a) If the object is dropped from a 100 m high

tower.​

Answer 1

Answer:

ches the ground vd compare to the speed of the rock when it is thrown upward vu?

____vd > vu____vd = vu____vd < vu

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Sage Luong

2 years ago

Posted 2 years ago. Direct link to Sage Luong's post “*note: the _ symbol refers to a subscript. So, v_f...”

Great Answer

Good Answer

*note: the _ symbol refers to a subscript. So, v_f refers to the final velocity.

Sorry, but I believe the acceleration is -5m/(s^2).

x_f = x_i + v_i(t) + 0.5at^2

0m = 100m + (15m/s)(10s) + 0.5a(10s)^2

-100m = 150m + 50s^2a

-250m = 50(s^2)a

a = -5m/s^2

Now to the answer. The velocity as the rock reaches the ground will be greater than the initial velocity. Just try substituting values to test this out.

v_f = v_i + at

v_f = 15m/s - 5m/s^2(10s)

v_f = 15m/s - 50m/s

v_f = -35m/s

speed_f = |v_f|

speed_f = |-35m/s|

speed_f = 35m/s

Therefore, speed_f > speed_i.

Explanation:

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Answer 2

if object is dropped from height then it will perform dynamic motion and it is under free fall condition