Hiiiii!!! Can someone pls help me with this question below
Identify the type of motion of an object in the
following cases:
(a) If the object is dropped from a 100 m high
tower.
Answers
Answer:
ches the ground vd compare to the speed of the rock when it is thrown upward vu?
____vd > vu____vd = vu____vd < vu
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Sage Luong
2 years ago
Posted 2 years ago. Direct link to Sage Luong's post “*note: the _ symbol refers to a subscript. So, v_f...”
Great Answer
Good Answer
*note: the _ symbol refers to a subscript. So, v_f refers to the final velocity.
Sorry, but I believe the acceleration is -5m/(s^2).
x_f = x_i + v_i(t) + 0.5at^2
0m = 100m + (15m/s)(10s) + 0.5a(10s)^2
-100m = 150m + 50s^2a
-250m = 50(s^2)a
a = -5m/s^2
Now to the answer. The velocity as the rock reaches the ground will be greater than the initial velocity. Just try substituting values to test this out.
v_f = v_i + at
v_f = 15m/s - 5m/s^2(10s)
v_f = 15m/s - 50m/s
v_f = -35m/s
speed_f = |v_f|
speed_f = |-35m/s|
speed_f = 35m/s
Therefore, speed_f > speed_i.
Explanation:
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if object is dropped from height then it will perform dynamic motion and it is under free fall condition