Question

hiiiii frndss please... .
21 and 22.. please.. please

Answer 1

Question no.21


Let the numbers be ( a - d ) , a , ( a + d ).


Given,


⇒Sum of the terms = -3


⇒( a - d ) + a + ( a + d ) = -3


⇒a - d + a + a + d = -3


⇒3a = -3


⇒ a = ( -3 ) ÷3


•°• a = -1


Now,


⇒Product of numbers = 8


⇒ ( a - d ) ( a + d ) a = 8


Using identity,


⇒ ( x + y ) ( x - y ) = x² - y²


⇒ ( a² - d² ) a = 8


Substituting the value of ( a = -1 ),


⇒ [ ( -1 )² - d² ] ( -1 ) = 8


⇒ [ 1 - d² ] ( -1 ) = 8


⇒ -1 + d² = 8


⇒ d² = 8 + 1


⇒ d² = 9


⇒ d = √9


•°• d = 3


Now,


Numbers = ( a - d ) , ( a ) , ( a + d )


= [ ( -1 ) - 3 ] , ( -1 ) , [ ( -1 ) + 3 ]


= ( -1 - 3 ) , ( -1 ) , ( -1 + 3 )


= ( -4 ) , ( -1 ) , ( 2 )


Hence, the numbers are -4 , -1 and 2.


Question no.22


Given,



Ram Prasad saved Rs.10 in First week and his weekly saving is increased by Rs.2.75 , in nth week his savings became Rs.59.50.


So here,


It will form an A.P.


Where,


First term (a ) = Rs.10


Common difference ( d ) = Rs.2.75


nth term = Rs.59.50


Using formula,


⇒nth term = a + ( n - 1 )d


⇒ Rs. 59.50 = Rs. 10 + ( n - 1 ) Rs. 2.75


⇒ Rs. 59.50 = Rs. 10 + Rs.2.75n - Rs.2.75


⇒ Rs. 59.50 - Rs.10 + Rs.2.75 = Rs.2.75n



⇒ Rs. 62.25 - Rs. 10 = Rs. 2.75n



⇒ Rs. 52.25 = Rs. 2.75n


⇒Rs. 52.25 ÷ Rs. 2.75 = n


•°• n = 19

Hope it helps!!

Answer 2

Answer:

friend answer is 22 to hope it helps you