Question

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don't post irrelevant answers ​

Answer 1

Answer:

2: second is answer of the following

Answer 2

(cosθ/(1+sinθ))+ ((1-sinθ)/cosθ)

Take only the cosθ/1+sinθ for now

Multiply by 1-sinθ and divide by 1-sinθ also.

∴(cosθ/(1+sinθ))((1-sinθ)/(1-sinθ))

cosθ(1-sinθ)/1-sin^2 θ

cosθ(1-sinθ)/cos^2 θ

(1-sinθ)/cosθ

∴cosθ/(1+sinθ)=(`1-sinθ)/cosθ

∴The equation will become

cosθ/(1+sinθ) + (1-sinθ)/cosθ

= (1-sinθ)/cosθ + (1-sinθ)/cosθ

=2(1-sinθ)/cosθ

2secθ(1-sinθ)

2secθ-2secθsinθ

2secθ-(2sinθ/cosθ)

2secθ-2tanθ

2(secθ-tanθ)

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