Math, asked by Anonymous, 10 months ago

Hiiiiii guys!!

At a party, everyone shook hands with everybody else. There were 66 handshakes. How many people were at the party?

Answers

Answered by Anonymous
11

Hi✌️✌️

lets say there are n persons

first person shakes hand with everyone else: n-1 times(n-1 persons)

second person shakes hand with everyone else(not with 1st as its already done): n-2 times

3rd person shakes hands with remaining persons: n-3

So total handshakes will be = (n-1) + (n-2) + (n-3) +…… 0;

= (n-1)*(n-1+1)/2 = (n-1)*n/2 = 66

= n^2 -n = 132

=(n-12)(n+11) = 0;

= n = 12 OR n =-11

-11 is ruled out so the answer is 12 persons.

I hope it will help you....

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Answered by Anonymous
3

Answer:

12

Step-by-step explanation:

Let's start with small numbers of people and handshakes and move from there. I'll represent people with letters to show the handshakes:

If we have 2 people, there is 1 handshake (AB) .

If we have 3 people, there are 3 handshakes (AB,AC,BC) .

If we have 4 people, there are 6 handshakes (AB,AC,AD,BC,BD,CD).

If we have 5 people, there are 10 handshakes

(AB,AC,AD,AE,BC,BD,BE,CD,CE,DE).

See that we can express the number of handshakes as the sum of consecutive positive integers, starting with 1, i.e.

1+2+3+...+(n−1)

and the number of people present is

n

Let's test this with 5 people. We have

1+2+3+4=10 handshakes.

n−1=4⇒n=5 which is the number of people.

So what we need to do is add up to 66 and we'll be able to find the number of people:

1+2+3+4+5+6+7+8+9+10+11=66⇒

⇒n−1=11⇒n=12

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