Question

Hiiiiii !!!!!





Please answer this question ! it's urgent ! ​

Answer 1

Step-by-step explanation:

u refer above the picture...

i hope it will help u

please mark as brainliest answer

Answer 2

QUESTION :-

$\rm\frac{sin \theta}{1 - cosec \theta} + \: \frac{cosec \theta}{1 - sin \theta} = 1 + sin \theta \: + cosec \theta$

SOLUTION :-

$\rm \implies \red {\underline{LHS:- }} \: \: \: \frac{sin \theta(1 - sin \theta) + cosec \theta(1 - cosec \theta)}{(1 - cosec \theta) \: \: (1 - sin \theta \: )} \\ \rm \implies \: \frac{sin\theta - sin {}^{2} \theta + cosec\theta - cosec {}^{2}\theta }{(1 - cosec {}^{2}\theta) \: \: (1 - sin \theta)} \\ \rm \implies \: \frac{sin\theta(1 - sin\theta) + cosec\theta(1 - cosec\theta)}{(1 - cosec\theta) \: \: (1 - sin\theta)} \\ \rm \implies \: \frac{sin\theta \: + cosec\theta \: + \cancel{(1 - sin\theta)} \: \: \cancel{(1 - cosec\theta)}}{ \: \cancel{(1 - cosec\theta)} \: \: \: \cancel{(1 - sin\theta)} } \\ \rm \implies \: sin \theta \: + \: cosec\theta \: + 1 \: \\ \rm \implies \purple {\underline{RHS:- }} \: \: .°. \: 1 + sin\theta\: + cosec\theta \:$

$\implies\green{\underline{\boxed{LHS =RHS}}}$

SOME IDENTITIES RELATED TO TRIGONOMETRY.

1)$\rm{ sin^2\theta + cos^2\theta= 1}$

2)$\rm{ 1 + cot^2\theta= cosec^2\theta }$

3) $\rm{1+tan^2\theta = sec^2\theta}$