Question

hiker stands on the edge of a cliff 490 above all the ground and drop stone . find the time taken by stone to reach the ground and hits the ground. (g=98ms square)​

Answer 1

h=490m

u=0m/s

g=9.8m/s^2

h=ut+1/2gt^2

490=0+1/2*9.8*t^2

t^2=490/4.9=100

t=10

so required time is 10 seconds.