Question

Himadas, a sprinter,
runs
with
constant
velocity 3 m/sec
through a forest. A
fruit from tree
a
which is right above
him, starts to fall
from a height of 20
meters
when
Himadas
starts
running. How far
behind Himadas will
the fruit land?​

Answer 1

Answer:

6.06 m behind Himadas will fruit land

Explanation:

Himadas content velocity =3 m/sec

Apple distance from ground =20 m

so time taken by apple to ground

h=ut+1/2at²

20=0*t+1/2*9.8*t²

t²=20/4.9

t=√(20/4.9)=2.02sec

Now distance travelled by Himadas

=velocity *time =3*2.02=6.06 m

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