Question

Himani checked coin collection and found that she had 150 coins in the denominations of rupees 1 rupees ,2 rupees and rupees 5 half of them over rupees 2coins and the number of rupees 1 coins was twice that of 5 rupees coins. if the total amount of rupees 325 how many coins of each denominations does Himani has in her collection​

Answer 1

Let number of Rs5 coins be x

Number of Rs 2 coins =3× Number of 5 Rs coins =3x

Number of Re1 coins =160−(x+3x)

=160−4x

Amount of Rs5 coins =5×x=5x

Amount of Rs2 coins =2×3x=Rs6x

Amount of Re1 coins =(160−4×x)

=160−4x

As per the question, Total amount =Rs300

160−4x+5x+6x=300

7x=300−160

x=  

7

140

​

 

x=20

Number of Re 1 coins =160−4x

=160−4×20

=80

Number of Rs2 coins =3x=3×20=60

Number of Rs5 coins =x=20

Answer 2

Answer:

rs 1=2x

rs 2=75(half of then is 2 , so 150 half is 75)

rs =x

Step-by-step explanation:

rs 1=2x

rs 2=75(half of then is 2 , so 150 half is 75)

rs =x

75 +x+ 2x=150

75+3x=150

3x=150-75

3x=75

x=75/3

x=25

rs 1=2x =2×25 50

rs 2=75

rs =x=25