Hind length of bingent dancen from a pint akase dibence
from the contre of the circle is inom Given that the
audius of antion cloche is home
;
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Perimeter of semicircle = \pi r+2rπr+2r
We are given that The length of a chain used as a boundary of a semicircular park is 108m.
So, \pi r+2r =108πr+2r=108
\frac{22}{7}r+2r =108
7
22
r+2r=108
\frac{22r+14r}{7} =108
7
22r+14r
=108
\frac{36r}{7} =108
7
36r
=108
r =108 \times \frac{7}{36}r=108×
36
7
r =21r=21
Area of semicircle = \frac{\pi r^2}{2}
2
πr
2
= \frac{\frac{22}{7} \times 21^2}{2}
2
7
22
× 21
2
= 693693
Hence the area of the park is 693 sq.m.
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