Question

Hind meet requivalent resistance between
two paints A&B

52
0
a 오
ma
AAAAA
52
352
.
8502
A
B​

Answer 1

Answer:

13.33 ohms

Explanation:

R(AB)= 5+[10/(1+2)]+5 =5+3.33+5 =13.33 ohms

Answer 2

Req = 13.34 Ω

Given

A circuit is given having 5 - 5 Ω resistors

To Find

Equivalent resistance b/w A and B

Knowledge Required

If resistors are connected in series ,

$\bf \pink{\bigstar\ \; R_{eq}=R_1+R_2+R_3+...}$

If resistors are connected in parallel ,

$\bf \green{\bigstar\ \; \dfrac{1}{R_{eq}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}+\dfrac{1}{R_3}+...}$

Solution

Observe attachment ,

2 , 3 are in series ,

$\to \rm R_{23}=5+5\\\\\to \bf R_{23}=10\ \Omega$

23 and 4 are in parallel ,

$\to \rm \dfrac{1}{R_{234}}=\dfrac{1}{R_{23}}+\dfrac{1}{R_4}\\\\\to \rm \dfrac{1}{R_{234}}=\dfrac{1}{10}+\dfrac{1}{5}\\\\\to \rm \dfrac{1}{R_{234}}=\dfrac{3}{10}\\\\\to \bf R_{234}=\dfrac{10}{3}\ \Omega$

1 , 234 , 5 are connected in series ,

$\to \rm R_{12345}=R_1+R_{234}+R_5\\\\\to \rm R_{12345}=5+\dfrac{10}{3}+5\\\\\to \rm R_{123345}=10+\dfrac{10}{3}\\\\\to \rm R_{12345}=\dfrac{40}{3}\\\\\bf \to R_{12345}\cong 13.34\\\\\bf \to \red{R_{eq}\cong 13.34\ \Omega\ \; \bigstar}$