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Answers
Rate of descending the elevator = 7m/min
It start descend from 9 m above the ground level.
To Find:-
How long will it take to reach -205 m
Solution:-
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀According to the Question
It is given that elevator descends in to a mine shaft at the rate of 7m/min .If its descent starts from 9m above the ground level. we have to calculate the time taken to reach -205 m . So let's begin
As the elevator descend 9 m above from the ground level.
So , the distance descended by the elevator = -205 + (+9)
:\implies:⟹ -196m
Now it is given that the rate of descending the elevator is 7m/min. (we take the rate of descending in negative )
Let the time taken by the elevator be t min .
Therefore,
:\implies:⟹ rate = Distance/time
Substitute the value we get
:\implies:⟹ -7 = -196/t
:\implies:⟹ 7 = 196/t
:\implies:⟹ 7×t = 196
:\implies:⟹ t = 196/7
:\implies:⟹ t = 28 minutes
Hence, the time taken by the elevator is 28 minutes.