Hint given : Use tan (A + B) = tan (45° - C)
Topic : Trigonometry
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Here the required and expected thing that you should know is the triple angle formula for tan function.
So, this is a very important Formula and i recommend you to learn this
tan (A+B+C) = (tan A + tan B + tan C - tanAtanBtanC)/1-tanAtanB-tanBtanC-tanAtanC
So,
If A+B+C=45°
So,
tan(45°) = 1 = tan A + tanB+ tanC - tan AtanBtanC/1-tanAtanB-tanBtanC-tanAtanC
So,
tanA+tanB+tanC - tanAtanBtanC = 1-tanAtanB-tanBtanC-tanAtanC
So,
tanA+tanB+tanC + tantanB + tanBtanC + tanAtanC = 1+tanAtanBtanC
Now,
remember,
sigma tanA = tan A + tan B + tanC
which actually sigma in simple terms means the sum of all the like terms occurring in the equation.
So,
we've got
Sigma tan A + sigma tan A tanB = 1 + tan A tan B tan C
Now,
Product of all like terms is represented by π
So,
atlast
sigma tan A + sigma tanAtanB = 1+π tanA
So, the correct answer will be (c)
Hope this helps you !
So, this is a very important Formula and i recommend you to learn this
tan (A+B+C) = (tan A + tan B + tan C - tanAtanBtanC)/1-tanAtanB-tanBtanC-tanAtanC
So,
If A+B+C=45°
So,
tan(45°) = 1 = tan A + tanB+ tanC - tan AtanBtanC/1-tanAtanB-tanBtanC-tanAtanC
So,
tanA+tanB+tanC - tanAtanBtanC = 1-tanAtanB-tanBtanC-tanAtanC
So,
tanA+tanB+tanC + tantanB + tanBtanC + tanAtanC = 1+tanAtanBtanC
Now,
remember,
sigma tanA = tan A + tan B + tanC
which actually sigma in simple terms means the sum of all the like terms occurring in the equation.
So,
we've got
Sigma tan A + sigma tan A tanB = 1 + tan A tan B tan C
Now,
Product of all like terms is represented by π
So,
atlast
sigma tan A + sigma tanAtanB = 1+π tanA
So, the correct answer will be (c)
Hope this helps you !
arnab2261:
Thanks, bhaiya.. ☺️
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