[Hint. Let the numbers be 7x, 7x + 7 a
4. Divide 534 into three parts such th
be 18 more than the first.
5. Three times the smallest of three
Find the numbers.
6. One number is 7 more than anot
What are the numbers ?
Th
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Step-by-step explanation:
Given Divide 534 into three parts such that second part will be 32 less than twice the first and third will be be 18 more than the first. Find the numbers.
Three times the smallest of three consecutive odd numbers decreased by 7 equals twice the largest one. Find the numbers.
One number is 7 more than another and its square is 77 more than the square of the smaller number. What are the numbers?
- Let the number be a
- According to the question, second part is 32 less than twice the first.
- So it will be 2x – 32
- Third is 18 more than first.
- So 18 + a
- Now we get the equation as
- a + (2a – 32) + (18 + a) = 534
- 4a – 14 = 534
- 4a = 14 + 534
- 4a = 548
- Or a = 137
- Now a = 137
- 2a – 32 = 2(137 ) – 32
- = 242
- 18 + a = 18 + 137
- = 155
- So the numbers are 137, 242 and 155
- Let the numbers be a, a + 2, a + 4
- According to question
- 3a – 7 = 2(a + 4)
- 3a – 7 = 2a + 8
- So a = 15
- Now a + 2 = 17
- Also a + 4 = 19
- Let a be the smaller number and a + 7 be the larger number
- So (a + 7)^2 = a^2 + 77
- So a^2 + 14a + 49 = a^2 + 77
- 14a = 28
- Or a = 2
- So a + 2 = 9
Reference link will be
https://brainly.in/question/1383557
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