Question

Hiralal want to cover the floor of a hall 5 metre and 6 metre long bi square tile if square tile is of side 20 cm then find the number of tiles required to cover the floor of the hall

Answer 1

Step-by-step explanation:

no.of tiles required= area of floor/area of one tile

area of floor= length×breadth

area of floor=6m×5m

area of floor=30m^2

1m=100cm

20cm=0.2m

area of one square tile=side × side

area of one square tile=(0.2)^2

area of one square tile=0.04m^2

no.of tiles required=area of floor/area of one tile

no.if tiles required=30/0.04

no.of tiles required=750

Answer 2

$\tt ฏGIVEN:−$

$\tt length \: of \: floor = 4m =400cm$

$\tt breadth\: of \: floor= 3m = 300cm$

$\tt length\: of \: single \: tile= 8cm$

$\tt breadth\: of \: single \: tile= 6cm$

$\tt ฏFIND:-$

$\tt no. \: of \: tiles \: reqire = ?$

$\tt ฏSOLUTION:-$

$\tt area \: of \: floor = 400 \times 30 \\ \tt = 120000 {cm}^{2}$

$\tt area \: of \: each \: tile= 8 \times 6 = 4 {cm}^{2}$

$\tt now \: let \: no. \: of \: tiles = x$

$\tt = > area \: of \:hall= x\times area \: of \: each$

$\tt = > 120000 = x(48)$

$\tt = > x = \frac{ \cancel{ 120000}}{ \cancel{48}} = 2500$

$\boxed{ \tt so \: total \: no. \: of \: tile \: is \boxed{2500}}$