Question

Hiranpur is a hill station. Binny lives in Hiranpur with his parents. The temperature of Hiranpur at
12 noon was. 10°C above zero. It decreased at the rate of 2°C per hour untill mid-night. On that night. Binny was suffering from high fever. The hospital was 5 km away from his residence. It was very cold outside and there was no vehicle available. In spite of this, his father managed to take him to the nearest hospital
(a) At what time would the temperature of Hiranpur be 0°C?
(b) At what time would the temperature of Hirapur be 8°C below zero?
(c) What would the temperature of Hiranpur at mid-night?
(d) Which value did Binny's father depict?​

Answer 1

Solution :-

At 12 noon, the temperature = 10° C above zero

The temperature is decreasing at 2° C per hour

8° C below zero = - 8° C

So, total fall in temperature from 10° C to 0° C and from 0° C to - 8° C = 18° C

Since the temperature falls 2° C in every one hour.

Therefore, to decrease 18° C, time taken = 18/2

= 9 hours

Present time is 12 noon so, the time when the temperature is - 8° C

= 12 noon + 9 hours

So, The time at which the temperature will be - 8° C = 9 PM

At 9 PM, the temperature is - 8° C, the temperature at 12 midnight will be = 

(- 8° C) + (- 2° C × 3 hours)

= (- 8° C) + (- 6° C)

= - 14° C

So, at 12 midnight the temperature will be - 14° C.

Answer.

STEP BY STEP EXPLATION...

Rate of decreasing temperature in 1 hour 2.C

Rate of decreasing in half hour 1.C

Now,

Total temperature 10.C+8.C

18.C

The time when the temperature be 8.C below zero 1/2 multiplied 18.C

9pm

Temperature at mid night -8.C-6.C

-14.C

....

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