Hiroto solved the equation 6 – 4|2x – 8| = –10 for one solution. His work is shown below. 6 – 4|2x – 8| = –10 –4|2x – 8| = –16 |2x – 8| = 4 2x – 8 = 4 2x = 12 x = 6 What is the other solution? –6 –4 2 10
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Answer:
The solution set is
x = { 6 , 2 }
Step-by-step explanation:
Since we are given that
6 – 4|2x – 8| = –10
⇒ – 4|2x – 8| = –10 -6 = -16
⇒ – 4|2x – 8| = -16
⇒ |2x – 8| = 4
by using definition of mode we get
2x – 8 = ± 4
either 2x – 8 = 4 or 2x – 8 = - 4
Case 1
2x – 8 = 4
⇒ 2x = 12
⇒ x = 6
Case 2
2x – 8 = - 4
⇒ 2x = - 4 + 8 = +4
⇒ 2x = 4
⇒ x = 2
Thus the solution set is
x = { 6 , 2 }
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