Question

His father's age is 4 times that of his son after 5 years it will be three times that of his son how many more years will be take if father's age is to be twice of his son​

Answer 1

Answer:

20 years from now

Step-by-step explanation:

f = father's age

s = son's age

f = 4s

f+5 = 3(s+5)

4s+5 = 3(s+5)

4s +5 = 3s + 15

4s-3s = 10

s=10 son is currently 10

f = 40 father is currently 40

n = years from the present

n + 40 = 2( n+10)

n + 40 = 2n + 20

40 = 2n - n +20

n = 20