Question

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Calculate the volume of 80% H2SO4 (density = 1.80g/cc) required to prepare one litre of 20% H2SO4 (density = 1.25g/cc).
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Answer 1

use the formula

use the formulam=10xd/m2

use the formulam=10xd/m2m=molarity

use the formulam=10xd/m2m=molarityx=%by mass=80/100

use the formulam=10xd/m2m=molarityx=%by mass=80/100d=density of h2so4=1.8

use the formulam=10xd/m2m=molarityx=%by mass=80/100d=density of h2so4=1.8m2=molar mass of h2so4=98

use the formulam=10xd/m2m=molarityx=%by mass=80/100d=density of h2so4=1.8m2=molar mass of h2so4=98keeping the values we get.......................

use the formulam=10xd/m2m=molarityx=%by mass=80/100d=density of h2so4=1.8m2=molar mass of h2so4=98keeping the values we get.......................m=0.146 molar

use the formulam=10xd/m2m=molarityx=%by mass=80/100d=density of h2so4=1.8m2=molar mass of h2so4=98keeping the values we get.......................m=0.146 molar

use the formulam=10xd/m2m=molarityx=%by mass=80/100d=density of h2so4=1.8m2=molar mass of h2so4=98keeping the values we get.......................m=0.146 molar now use.............

use the formulam=10xd/m2m=molarityx=%by mass=80/100d=density of h2so4=1.8m2=molar mass of h2so4=98keeping the values we get.......................m=0.146 molar now use.............m1v1=m2v2

use the formulam=10xd/m2m=molarityx=%by mass=80/100d=density of h2so4=1.8m2=molar mass of h2so4=98keeping the values we get.......................m=0.146 molar now use.............m1v1=m2v2(0.146)(v)=(0.2)(1)

use the formulam=10xd/m2m=molarityx=%by mass=80/100d=density of h2so4=1.8m2=molar mass of h2so4=98keeping the values we get.......................m=0.146 molar now use.............m1v1=m2v2(0.146)(v)=(0.2)(1)v=1.369 liters-------------answer

Answer 2

Hey mate...

here's the answer...

calculate the molarity of 80% acid solution which will act as stock solution.

By using the given density 1.8 g/mL

1800 g for 1 litre

Thus, 80% X 1800 =1440g acid  required

Since, molarity = weight taken/ formulae weight

=> 1440/98.80= 14.68 M

Now you have molarity of your stock solution 14.68M

In next step you require 0.2 M acid solution from 14.68M stock solution.

You can use the formulae

   M1 V1= M2V2

volume required (V1) = 0.2 X 1000 / 14.68 = 13.62 ml

13.62 ml of 80 % sulphuric acid is required.

Hope this helps❤