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Answered by
0
Answer:
let the LCM and HCF be a and b
according to question,
a:b=16:11
let a=16x then, b=11x
again, a+b=4956
16x+11x=4956
27x=4956
x=4956/27
a=16*4956/27
b=11*4956/27
Answered by
4
Answer:
let the LCM and HCF be a and b
according to question,
a:b=16:11
let a=16x then, b=11x
again, a+b=4956
16x+11x=4956
27x=4956
x=4956/27
a=16*4956/27
b=11*4956/27
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