Math, asked by Anonymous, 11 months ago

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Answered by rajugupta9954
0

Answer:

let the LCM and HCF be a and b

according to question,

a:b=16:11

let a=16x then, b=11x

again, a+b=4956

16x+11x=4956

27x=4956

x=4956/27

a=16*4956/27

b=11*4956/27

Answered by Anonymous
4

Answer:

let the LCM and HCF be a and b

according to question,

a:b=16:11

let a=16x then, b=11x

again, a+b=4956

16x+11x=4956

27x=4956

x=4956/27

a=16*4956/27

b=11*4956/27

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