Question

hlo anybody pls answer the qstn....!!!!

If zeroes of the polynomial
${x}^{2} + 4x + 2a$
are
$\alpha \: \: \: and \: \: \: \frac{2}{ \alpha }$
then find the value of "a" ​

Answer 1

Answer:

So simple buddy

Compare x^2 + 4x +2a with ax^2 + bx +c

a = 1, b= 4, c= 2a

Now,

A/Q

It's zeros are Alpha and 2/Alpha

Product of zeros = c/a

Alpha × 2 /Alpha = 2a

Alpha will be cancelled

2 = 2a

a = 1

Soo simple ☺️

Answer 2

This is ur answer buddy ❤️