hlo dudes ,
give me the answer of this question with complete explanation--
Q => Find the sum of all natural numbers from 75 to 97 .
Answers
Answered by
1
refer the pic..
hope it'll help..
mark it as brainliest..
hope it'll help..
mark it as brainliest..
Attachments:
Anonymous:
good
Answered by
0
Let a be the first term and d be the common difference.
First term a = 75.
Common difference d = 1
Last term an = 97.
We know that an = a + (n - 1) * d
97 = 75 + (n - 1) * 1
97 = 75 + n - 1
97 = 74 + n
97 - 74 = n
23 = n.
Now,
Sum of n terms = n/2(a + l)
= 23/2(75 + 97)
= 23/2(172)
= 23 * 86
= 1978.
Therefore the sum of natural numbers from 75 to 97 = 1978.
Hope this helps!
First term a = 75.
Common difference d = 1
Last term an = 97.
We know that an = a + (n - 1) * d
97 = 75 + (n - 1) * 1
97 = 75 + n - 1
97 = 74 + n
97 - 74 = n
23 = n.
Now,
Sum of n terms = n/2(a + l)
= 23/2(75 + 97)
= 23/2(172)
= 23 * 86
= 1978.
Therefore the sum of natural numbers from 75 to 97 = 1978.
Hope this helps!
Similar questions